OzFab
Well-known member
I solved this some 20 years ago when google was what you did with your eyes and a pretty girl. ..... (or was that oogle?)
Drop another letter & you're there

I solved this some 20 years ago when google was what you did with your eyes and a pretty girl. ..... (or was that oogle?)

Drop another letter & you're there![]()
How would you answer these 4 questions?
#1- How would you put a giraffe in a refrigerator?
#2- How would you put an elephant in a refrigerator?
#3- The Lion King is hosting an animal conference. All animals attend, except one. Which animal does not attend?
#4- There is a river you must cross, but it is known to be frequented by crocodiles, and you do not have a boat. How do you manage?
#1 open door, put giraffe in, close door.
#2 open door, get giraffe out, put elephant in, close door
#3 the lion king, he's the host.
#4 use the bridge
'sid
[EDIT]
Only 2 out of 4 this time.
Let's keep the twelve coins.
you get blindfolded and in front of you, there are twelve coins, six facing up, six down.
you cannot tell by feeling them which way is which...
you're given the task to divide the unsorted coins into two groups, each of them has to have the same amount of coins facing up...
what do you do?
Only 2 out of 4 right this time. .....
Well.. that's the answers we considered correct when we asked those questions in elementary school
okay, it wasn't a giraffe but a rhino,
it wasn't the lion king but a giraffe, and
it wasn't crocodiles but piranhas (the amazon specifically)
*shrugs*
wait.. if it's an african river, then the crocodiles will be at the conference
'sid
[EDIT]
DOH!!
Dammit.. the elephant is still in the fridge (must read before post... *grmpf*)

I cannot mark, but I can seperate them, right? I need nothing but a box to put original coins in
(together with the table for possible fake coins and scale for.. well scaling)
Well I'll try.
I make three groups A, B and C with four coins each
Best Case scenario
I.a.
balancing A against B is levelled
All coins on the scale go into my box of original coins.
The coin is in the remaining group of four.
II.
balancing three coins of the last group against three coins known to be valid
leave one coin on the table
II.a.
BALANCED scale:
the last coin not in the box, nor on the scale is the fake coin.
III.
balance fake coin against real coin to know if it's lighter or heavier
II.b.
UNBALANCED scale:
I now know if the coin is lighter or heavier. (just say heavier here)
III.
weigh two of the three possible fake coins against each other
the other on the table (rest into the box)
III.a.
BALANCED scale:
the last coin is the fake coin (and I know it's the heavier one)
III.b.
UNBALANCED scale:
the last coin is the heavier one on the scale.
second scenario:
I.b.
balancing A against B is NOT levelled (let's just say A is heavier; if not I change the names A->B & B<-A)
the remaining coins on the table go into my box of original coins.
II.
three coins on both sides of the scale two from group A and one of group B each.
the other two coins stay on the table.
II.a.
BALANCED scale:
I now know that the fake coin is lighter (since it was a B-coin previously)
and that it is still on the table
weigh the coins on the table against each other.. the lighter is fake
II.b.
UNBALANCED scale:
Now it's getting messy.. since I think I need to know if the coins are from the A or the B group originally,
but without a marking that seems rather impossible.
let's assume I do know by laying all A coins face up and all B coins face down...
III.
measure the two formerly A-group coins of the HEAVIER side
lay the B-coin of the other group on the table (rest into the box)
III.a.
BALANCED scale:
the fake coin is the one 'lighter' coin of the formerly B group from the second go.
III.b.
UNBALANCED scale:
the fake coin is the heavier coin on the scale.
If I do not mark the coins in the second process I don't know, I need to think of it some more
'sid
You can't have a box.lol. You don't need one. You don't need "A's" and "B's". You are very close to having this solved. Hell- you may have it solved but I'm going to have to read the last part about another dozen times to make sure I know what you mean.
For instance- you have 12 coins........ so the counterfeit should be obvious.
If the first 8 don't balance- the solution should be just as easy to explain as the previous.
That would make 4 out of 4- How do you forget you have an elephant in the fridge?![]()


Hints:Puzzle:
A
AA
BA
ABAA
AAABBA
CABBAA
ACAABBBA
AAACBACBAA
...........
what's the next line
Let's keep the twelve coins.
you get blindfolded and in front of you, there are twelve coins, six facing up, six down.
you cannot tell by feeling them which way is which...
you're given the task to divide the unsorted coins into two groups, each of them has to have the same amount of coins facing up...
what do you do?
Hints:
first step: change letters to numbers..
read the first two lines out loud (letter by letter, or digit by digit)
OK- Hmmm, blindfold on.....solution#2....Separate the coins into 2 groups of 6. Stack the coins. Grasp each stack between the thumb and forefingers and turn the stacks sideways on the table. You now have two groups of coins with the same amount of heads up-0.
Yeah, keep going...