If you want to do a belt tensioner, heres how it works
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While the engine is idling, the belt is loose. When you want to take off, just rev the engine a little and release the belt tensioner(i just realized i left a spring off the drawing). A spring pulls the tensioner against the slack side of the belt and pulls it tight.
What exactly is the ratio of the reduction unit? You can postulate about pulley size 'till the cows come, but it means nothing until you have some working numbers. As long as it's no deeper than about 6:1 you should be okay.
Oh sweet, thanks for the drawing. But my question is, if the spring is pulling up the tensioner how will i make it stay down (toggle) when i want to "engage clutch"?
what size tires do you plan on using? 6:1 is a pretty good ratio for around 16" tires. You can easily work with that, just do the belt tensioner, better than a centrifugal clutch IMO.
When dealing with multiple ratios, just multiply.
For example, 6:1 reduction box, with a 2:1 ratio between that and axle, 6:1x2:1=12:1
You need to know the diameter of the pocket bike tires, but im assuming its around 10" or 12", you can probably gear it a little higher than 6:1, so you may want to run a 1:1.5 ratio between the reduction box and axle, which would give you a 4:1 overall between engine and axle.
Sounds good. Thank you so much.