Masonisgreat35
Member
i am working on an idea for a two speed jackshaft based off of other 2 speed jackshaft setups and am wondering where to find sprag sprockets or one way sprockets witchever u call them
i cant seem to find any online that are either 3/4" or 5/8" bore, 20 teeth, pitch 35
anyone know of any manufacturers or a way to make one myself, i can have it welded together where needed but i cannot fabricate the components so i would need links to the peices that can then be assembled
also am i correct that the ratio from clutch 1 to sprag would be 2:1 so 6000rpm on crank will be 3000rpm on jackshaft?
when googling the formula to calculate it says as an example
the sprocket ratio is simply the number of teeth on the driving sprocket divided by the number of teeth on the driven sprocket
if the front sprocket has 20 teeth, and the rear sprocket has 80 teeth, the sprocket ratio is 20/80 = 1/4 = 1:4 so 4:1
following this formula as i understand it, they divided 20 by 80, witch would give u 0.25, instead of the 4 that they have as an answer.
but dividing 80 by 20 gives the correct answer of 4 instead of 0.25
am i not understanding the formula correctly?
as simplified as possible how would i calculate the ratio of two sprockets, and am i correct in thinking 10tooth to 20 tooth is 2:1 ratio or is it 1:2 ratio
attached is a picture of the idea, teeth count, and ratios, because the jackshaft is 5/8" ill be using a 3/4" to 5/8" steel keyed adapter so i can use 3/4" clutchs and sprockets
any feedback on the idea aswell as how to properly calculate ratios is welcome
thanks
i cant seem to find any online that are either 3/4" or 5/8" bore, 20 teeth, pitch 35
anyone know of any manufacturers or a way to make one myself, i can have it welded together where needed but i cannot fabricate the components so i would need links to the peices that can then be assembled
also am i correct that the ratio from clutch 1 to sprag would be 2:1 so 6000rpm on crank will be 3000rpm on jackshaft?
when googling the formula to calculate it says as an example
the sprocket ratio is simply the number of teeth on the driving sprocket divided by the number of teeth on the driven sprocket
if the front sprocket has 20 teeth, and the rear sprocket has 80 teeth, the sprocket ratio is 20/80 = 1/4 = 1:4 so 4:1
following this formula as i understand it, they divided 20 by 80, witch would give u 0.25, instead of the 4 that they have as an answer.
but dividing 80 by 20 gives the correct answer of 4 instead of 0.25
am i not understanding the formula correctly?
as simplified as possible how would i calculate the ratio of two sprockets, and am i correct in thinking 10tooth to 20 tooth is 2:1 ratio or is it 1:2 ratio
attached is a picture of the idea, teeth count, and ratios, because the jackshaft is 5/8" ill be using a 3/4" to 5/8" steel keyed adapter so i can use 3/4" clutchs and sprockets
any feedback on the idea aswell as how to properly calculate ratios is welcome
thanks